# Range of projectile

EmmaB03

## Homework Statement

[/B]
A bottle rocket can shoot its projectile vertically to a height of 26.0m. At what angle should the bottle rocket be fired to reach its maximum horizontal range, and what is that range? (You can ignore air resistance).

## The Attempt at a Solution

[/B]
For the first part: I think the angle the rocket should be fired is 45 degrees, because it's the optimal angle for projectiles, where it travels the furthest when launched at this angle; am I right?

For the second part: I have no idea what to do to start this part of the problem. I know that I now have the angle (45) and the height (26.0). I don't know where to go from this point.

Related Introductory Physics Homework Help News on Phys.org
MarkFL
I would begin with (and orienting our coordinate axes such that the initial position is at the origin ##\left(x_0,y_0\right)=(0,0)##):

##x(t)=v_0\cos(\theta)t\tag{1}##

##y(t)=-\dfrac{1}{2}gt^2+v_0\sin(\theta)t\tag{2}##

Solve (1) for ##t##, and substitute into (2)...what do you get?