- #1

- 57

- 0

I know that the range of that function is [tex](-\infty, 0) U (0, +\infty)[/tex]

But how do I get it? I'm having difficulties in isolating x. Can you explain it to me? Thank you. :)

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- Thread starter yik-boh
- Start date

- #1

- 57

- 0

I know that the range of that function is [tex](-\infty, 0) U (0, +\infty)[/tex]

But how do I get it? I'm having difficulties in isolating x. Can you explain it to me? Thank you. :)

- #2

HallsofIvy

Science Advisor

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[tex]f(1)= \frac{1- 1}{\sqrt{5+ 7- 1}}= \frac{0}{\sqrt{11}}= 0[/tex]

so 0 certainly

Since you have determined what x can be, what values of f do those values of x give?

- #3

- 534

- 1

Moreover, for sufficiently large |x|, the denominator is not real.

- #4

HallsofIvy

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- #5

uart

Science Advisor

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Halls, note that the function goes to +infinity at the lower end of it's domain and to -infinity at the upper end of it's domain and in continuous in between.

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