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Ranking charge stored on three capacitors by a battery
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[QUOTE="ChiralSuperfields, post: 6853259, member: 731016"] Thank you for your reply [USER=192687]@kuruman[/USER]! ##C_1## is in series with the battery ##C_2## and ##C_3## is in parallel with the battery Since ##C_2## and ##C_3## are parallel to each other their equivalent capacitance is ##C_2 + C_3##. I think what I did wrong with KVL was that I did not finding the equivalent capacitance of the capacitors in parallel. So if I replace branch's ##C_2## and ##C_3## with ##C_{23}## I get: [ATTACH type="full" alt="1675994162675.png"]322023[/ATTACH] So now ##V_1## and ##V_{23}## oppose the source, I think. ##\epsilon - V_1 - V_{23} = 0 ## ##\epsilon = V_1 + V_{23} ## So I think what I did wrong was that I applied KVL for the whole loop. Many thanks! [/QUOTE]
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Ranking charge stored on three capacitors by a battery
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