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Rate constant answer check

  1. Mar 24, 2009 #1
    Rate constant "answer check"

    1. The problem statement, all variables and given/known data
    given that activation energy for a certain reaction is 48 kJ/mol, and the rate constanct is 2.5 x 10-2 s-2 at 15 degrees Celsius. waht is the rate constant at 37 degrees Celsius?



    2. Relevant equations
    ln k1/k2 = [Ea/R] [(T1-T20)/(T1*T2)]


    3. The attempt at a solution
    my answer is k1= .1037740579 = .104 s-1


    thank you for all the help!!
     
  2. jcsd
  3. Mar 25, 2009 #2
    Re: Rate constant "answer check"

    Converting all temperatures to absolute and 48kJ to 48000 J so the units on the gas constant cancel I came up with 5.3*10^-3 s^-2

    I used this equation:

    ln k1/ln k2 = Ea/R(1/T2-1/T1)
     
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