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Homework Help: Rate of change derivative?

  1. Oct 11, 2012 #1
    Rate of change.... derivative?

    1. The problem statement, all variables and given/known data

    the total number of people(in millions) present in a population at a given time is given by the function:

    2t(5t+9)^1/2+12

    where t represents time (in hours) find the rate in change of the population after 2.5 hours...

    2. Relevant equations



    3. The attempt at a solution

    im so confused do i find the derivative ?
     
  2. jcsd
  3. Oct 11, 2012 #2

    Dick

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    Re: Rate of change.... derivate?

    Sounds like a good idea to me. The derivative is the rate of change.
     
  4. Oct 11, 2012 #3
    Re: Rate of change.... derivative?

    i got 10t+9..
     
  5. Oct 11, 2012 #4
    Re: Rate of change.... derivative?

    10(2.5)+9.... 34?
     
  6. Oct 11, 2012 #5

    Dick

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    Re: Rate of change.... derivative?

    Now how did you get that? Your expression looks like [itex]2 t \sqrt{5 t + 9}+12[/itex], is that right? Looks like you'll need the product rule and chain rule etc to differentiate it.
     
    Last edited: Oct 11, 2012
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