Imagine a trough filled with water (I can't put up a picture).(adsbygoogle = window.adsbygoogle || []).push({});

The water in the tank at time t seconds is given by [tex]V = 12x^2[/tex]. Given that water is flowing into the trough at the rate of [tex]60 cm^3/s[/tex], find the rate at which x is increasing when x = 10.

[tex]\frac{dV}{dx} = 24x[/tex]

[tex]\frac{d?}{ds} = 60 cm^3/s[/tex]

Then what do I do?

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# Homework Help: Rate of change

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