# Rate of climb

1. Oct 16, 2005

### mr_glass

I am having trouble with problem:

A plane needs 300 m to take off while going 88km/h. It then climbs with a constant speed of 88 km/h along a straight line, just celaring a power line 15m high at a horizontal distance of 460 m from it initial position.

I am asked to find the rate of climb of the plane.

I have figured out how to get the acceleration with

(Vf^2 - Vi^2)/2d a

but I do not know where to go from here.

2. Oct 16, 2005

### Tom Mattson

Staff Emeritus
Note: I've moved this from Advanced Physics to Introductory Physics.

The first thing that you need to recognize is that "rate of climb" means the same thing as "y-component of velocity while climbing". So the first thing you need to do is the angle that the plane's straight line trajectory makes with the horizontal. Since they give you the speed along that straight line tracjectory, finding the rate of climb should be easy after you get the angle.

3. Oct 18, 2005

### mr_glass

thanx i figured it out waasn't thinking clearly much easier thn what i was making it