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ihearyourecho
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Homework Statement
A single conducting loop of wire has an area of 7.2×10−2m2 and a resistance of 120 ohms. Perpendicular to the plane of the loop is a magnetic field of strength 0.50 T.
At what rate must this field change if the induced current in the loop is to be 0.39A?
Homework Equations
emf=(-NdeltaIB)/(deltat)
Rate of change = emf/-N
The Attempt at a Solution
emf=(-NdeltaIB)/(deltat)
Rate of change = emf/-N
It's a single loop, so N should be 1
Rate of change - emf/-1
emf=v=IR
Rate of change = -IR
Rate of change = -(.39A)*120ohms=-46.8
This isn't right though.
Thanks for the help :)
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