Imagine a cube that 'grows' by five cubic inches per week. How fast is its surface area increasing when the length of one of its sides is seven inches?(adsbygoogle = window.adsbygoogle || []).push({});

I know that the derivative of volume (V) with respect to time (t) is 5, e.g:

[tex] \frac{dV}{dt} = 5[/tex]

To calculate the surface area of a cube from a given volume I would use:

[tex] S=6(\sqrt[3]{V})^2 [/tex]

Therefore, would I need to calculate the derivate of S with respect to V in order to reach my goal of deriving S with respect to t?

Or am I going totally in the wrong direction?

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# Rates of change - confused (again!)

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