- #1

- 15

- 0

## Homework Statement

A person wants to move excess topsoil from his farm. He can hires a truck and driver for $60/h. The driver will take 30 mins to deliver a load of top soil. One person will take 40 h to load the truck with soil. Workers get $18/h (Including the time the truck takes). How many labourers should the person Hire?

## Homework Equations

Dunno :p

## The Attempt at a Solution

I figured that since it takes one person 40 hours, it should take two people 20 hours and 3 people 40/3 hours and so on...basically 40/x. That will represent the time it takes to move all the soil for one run. Then you must add the time for the driver to deliver with is 0.5 h. So the function for time is y = (40/x) + 0.5. That function will then be multiplied by the salary of both labourers and the driver which are 18x and 60. So i get:

= ((40/x) + 0.5)(18x) + ((40/x) + 0.5)(60)

= ((40/x) + 0.5)(18x + 30)

= 9x + 1200x^-1 + 735

Then I took the derivative and got

f'(x) = 9 -1200x^-2

To find the max slope should be 0

0 = 9 - 1200x^-2

1200/x^2 = 9

1200/9 = x^2

x = 11.54700

That does not match the answer in the back where it is 5 men that would make a total cost of $294