- #1

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problem:

i45.tinypic.com/xknbci.png

answer:

i50.tinypic.com/2qcnsyv.jpg

this is what i get...

i50.tinypic.com/124cxgy.jpg

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- Thread starter indigo1
- Start date

- #1

- 3

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problem:

i45.tinypic.com/xknbci.png

answer:

i50.tinypic.com/2qcnsyv.jpg

this is what i get...

i50.tinypic.com/124cxgy.jpg

- #2

SammyS

Staff Emeritus

Science Advisor

Homework Helper

Gold Member

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Hello indigo1. Welcome to PF !my question is... is this answer correct? for the last step. WOULDN'T you multiply 10[STRIKE]x[/STRIKE] by .5 and 12 by .2? the opposite of what this answer is? It says BASE is 10 in and BASE changes at .5 in per second

problem:

i45.tinypic.com/xknbci.png

answer:

i50.tinypic.com/2qcnsyv.jpg

this is what i get...

i50.tinypic.com/124cxgy.jpg

Why would you want to multiply the base by the rate of change of the base? Even your working has [itex]\displaystyle b\frac{dh}{dt}[/itex] and [itex]\displaystyle h\frac{db}{dt}\ .[/itex]

dh/dt

BTW: Below are your images, displayed so others can see them.

- #3

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But i was wondering if this is the same for my HW problem i applied the same A' equation but instead looked for the db/dt and i got -3/2 idk if this is right.

"The base of an isosceles triangle is 6 feet. If the altitude is 4 feet and increasing at the rate of 2 inches per minute, at what rate is the vertex angle changing?"

I will really appreciate for your help.

- #4

Mark44

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