(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two tubes carry the same incompressible fluid with viscosity 1.5 Pl. They have lengths L1 = 6 and L2 = 22 m and diameters d1 = 1.2 and d2 = 4.5 cm. What is the ratio of their flow rates F1/F2?

2. Relevant equations

Poiseuille's law: 8nLI/(pi*r^4)

while n is viscosity

L is the length

R is radius

3. The attempt at a solution

F1= (8*1.5*6*I) / (pi*(1.2/2)^4)

F2= (8*1.5*22*I) / (pi*(4.5/2)^4)

The ratio F1/F2 is:

(8*1.5*6*I) / (pi*(1.2/2)^4)* (pi*(4.5/2)^4)/ (8*1.5*22*I)

F1/F2= 46.296*1.1649= 53.932.

And this is wrong, can u help??

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# Ratio of Flow Rates.

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