1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Ratio of oxygen in atmosphere

  1. Mar 2, 2012 #1
    1. The problem statement, all variables and given/known data
    Air at sealevel is composed of 80% nitrogen and 20% oxygen, but at the top of Mount Everest the composition of air is different. Give an expression for the ratio ([itex]f_O[/itex]) of oxygen in the air as a function of height z above sealevel, assuming the temperature T is constant and the air is an ideal gas. The gravitational acceleration is g and the mass of a molecule of nitrogen is [itex]m_N[/itex] and the mass of a molecule of oxygen is [itex]m_O[/itex].

    3. The attempt at a solution

    The potential energy of a molecule of oxygen is [itex]m_O g z[/itex], so the probability of finding it at height z is: [itex]P_{mO}(z) \propto e^{-\frac{m_O g z}{k_B T}}[/itex]. Similarly for nitrogen: [itex]P_{mN}(z) \propto e^{-\frac{m_N g z}{k_B T}}[/itex]. So the ratio is simply [itex]f_O = \frac{e^{-\frac{m_O g z}{k_B T}}}{e^{-\frac{m_N g z}{k_B T}}} = e^{-\frac{(m_O - m_N)gz}{k_B T}}?[/itex]
     
  2. jcsd
  3. Mar 3, 2012 #2

    D H

    User Avatar
    Staff Emeritus
    Science Advisor

    No, it isn't. The troposphere is well mixed. That's why it's called the troposphere. Is this a problem from a physics text, or one that your teacher made up?

    I'll ignore this minor problem.

    That gives a ratio of one at sea level.

    Hint: Assume each gas is individually in hydrostatic equilibrium.
     
  4. Mar 3, 2012 #3
    Just a question my teacher came up with.

    The hydrostatic equation is [itex]dp = -\rho g dz[/itex] with [itex]dp = k_B T dn[/itex] and [itex]\rho = nm[/itex]:

    [tex]\frac{dn}{n} = -\frac{m_O g}{k_B T}dz, \Leftrightarrow \\
    \ln{\frac{n}{n_0}} = -\frac{m_O g }{k_B T}z \Leftrightarrow \\
    n = n(0) e^{-\frac{m_O g }{k_B T}z} [/tex]

    If I do the same thing for nitrogen and divide again I get the same answer, so I'm not sure what to do...
     
  5. Mar 6, 2012 #4
  6. Mar 6, 2012 #5

    D H

    User Avatar
    Staff Emeritus
    Science Advisor

    Correct.

    You do not get the same answer. Oxygen and nitrogen have different molar masses.

    Try computing nO(z)/ nN(z), the ratio of the oxygen density to nitrogen density. What does that tell you?
     
  7. Mar 6, 2012 #6
    Since [itex]n_n = n(0) e^{-\frac{m_N g }{k_B T}z}[/itex] I get [itex]\frac{n_O}{n_N} = \frac{n_0 e^{-\frac{m_O g }{k_B T}z}}{n_0 e^{-\frac{m_N g }{k_B T}z}} = e^{-\frac{(m_O - m_N) g }{k_B T}z}[/itex]...or am I missing something? Because that's the same thing I got in my original post.
     
  8. Mar 7, 2012 #7

    D H

    User Avatar
    Staff Emeritus
    Science Advisor

    You are assuming that oxygen and nitrogen have the same density at sea level (i.e., the same n0. They obviously don't since the the atmosphere at sea level is 80% nitrogen, 20% oxygen.
     
  9. Mar 7, 2012 #8
    You're right, so I should get [itex]\frac{0.8}{0.2}e^{-\frac{(m_O - m_N)g}{k_B T}z} = 4 e^{-\frac{(m_O - m_N)g}{k_B T}z}[/itex].
     
  10. Mar 7, 2012 #9

    D H

    User Avatar
    Staff Emeritus
    Science Advisor

    Correct. So now it's just a matter of plugging in the numbers with z=height of Everest and then converting the resulting nitrogen:eek:xygen ratio to the percentage of the air at the top of Everest that is oxygen.

    The result will be wrong (wrong in reality that is; the result will be correct for this homework problem). The makeup is still more or less 80%/20% ratio at the top of Everest. The troposphere is just too well-mixed for any disparities to show up. The upper reaches of the atmosphere (above the stratosphere) do exhibit this differentiation.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Ratio of oxygen in atmosphere
  1. Oxygen concentration (Replies: 1)

  2. Pluto's Atmosphere (Replies: 2)

  3. Mass of the atmosphere (Replies: 2)

  4. Atmosphere layers (Replies: 1)

Loading...