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Rational function integration

  1. Jan 14, 2009 #1
    Evaluate the integral:

    int ((x+1)/(x-1)) dx

    is this possible?

    i tried searching for this but there was no answer
     
  2. jcsd
  3. Jan 14, 2009 #2

    lurflurf

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    (x+1)/(x-1)=[(x-1)+2]/(x-1)=1+2/(x-1)

    Have you ever seen a function g such that g'=f'/f
    ?
     
  4. Jan 14, 2009 #3
    (x+1)/(x-1)=[(x-1)+2]/(x-1)=1+2/(x-1)

    could you please explain this?

    im having problems integrating ((x+1)/(x-1)) dx
     
  5. Jan 14, 2009 #4
    no wait, could you please fully solve the problem?
     
  6. Jan 14, 2009 #5

    HallsofIvy

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    If you cannot do basic algebra you are going to have great difficulty integrating any function. The above is just simple division. And you can see it is true just by adding the fractions on the right hand side.

    It would be much better for you to try yourself. Do you know the anti-derivative of 1/x?
     
  7. Jan 14, 2009 #6
    no, not yet but thank you
     
  8. Jan 14, 2009 #7

    HallsofIvy

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    Then why in the world are you trying to do this problem?
     
  9. Jan 15, 2009 #8
    Sorry, I just like to read ahead in my textbook
     
  10. Jan 15, 2009 #9

    HallsofIvy

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    Good! Just don't be upset if you are often puzzled!:rofl:
     
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