(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find two constants for 'a' and 'b' such that the verticle asymptote will be [tex]\pm[/tex] [tex]\frac{3}{5}[/tex]

y=[tex]\frac{ax^2+7}{9-bx^2}[/tex]

I rearranged so that it becomes [tex]-bx^2+8[/tex] in the denominator since i know that there are two roots that are [tex]\pm[/tex] it must be a square and since 3 is the numerator of the root it must -9 .... so i rearranged again to get

y=[tex]\frac{-ax^2-7}{bx^2-9}[/tex]

in which case i found the constant for a (-1) and [tex]5^2[/tex] is 25 so i found b as well so the equation would be

y=[tex]\frac{-x^2-7}{25x^2-9}[/tex]

is this right??? I have no way to check my answer so i just want to make sure :D

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# Homework Help: Rational Functions Question

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