1. The problem statement, all variables and given/known data Find an equation of a rational function f that satisfies the given conditions: vertical asymptotes: x=-3, x=1 horizontal asymptote: y=0 x-intercept: -1; f(0)= -2 hole at x=2 2. Relevant equations 3. The attempt at a solution Vertical Asymptotes are (x+3) and (x-1). Also (x-2) because of the hole (x+1) would go in the numerator because it corresponds with the x-intercept. I'm not sure where f(0)= -2 fits in this. (x+2) goes in the numerator because of the hole. (x+1)(x-2)/(x+3)(x-1)(x-2) The answer looks like 6x^2-6x-12/x^3-7x+6 so I'm obviously missing something, but I don't know what.