(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

2x-1

_____ > 0

5x+3

2. Relevant equations

3. The attempt at a solution

Just wondering, my teacher taught us that youre only supposed to look at what makes the denominator = 0, and dont look at the numerator because it has no affect on anything.

So, if i were to solve that id have to use -3/5

so, case 1 would be x < -3/5 which is -0.6, so if i plug in a number less like -1 into the bottom id get a negetive value, however am i plugging it in the top as well...? she said just look @ bot

or, suppose i have something with two vertical asymptotes like..

_(x+5)_______ < 0

(x+3) (x-1)

Im just looking at the values that make it negetive right? so -3, and 1. if i were to set a interval chart up and say x < -3 , i plug like -4 into (x+3) and into (x-1) and id get a negetive by a negetive which makes it positive. so the sign wouldnt flip on case 1

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# Rational inequality question

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