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Miracles

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can a non-factorable function has rational real roots?

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- Thread starter Miracles
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- #1

Miracles

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can a non-factorable function has rational real roots?

Last edited:

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Hootenanny

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Yes, for example take [itex]f(x):= x+a[/itex] where [itex]a \in \mathbb{Q}[/itex].can a non-factorable function has rational real roots?

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