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Rationalizing the denominator

  1. Jul 15, 2009 #1
    1. The problem statement, all variables and given/known data

    1/((i-s)^2)) how do i rationalize this , would i multpiy top and bottom by
    (i+s)^2
     
  2. jcsd
  3. Jul 15, 2009 #2

    tiny-tim

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    (rationalize? anyway …)

    Yup! :biggrin:
     
  4. Jul 15, 2009 #3
    k thank-you
     
  5. Aug 21, 2009 #4
    By the way, what is the proper term? (assuming "rationalize" is not)
     
  6. Aug 21, 2009 #5

    symbolipoint

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    "Rationalize" is the correct vocabulary for what you wanted.
     
  7. Aug 21, 2009 #6

    tiny-tim

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    Re: "Rationalizing"

    Hi Unit! Hi symbolipoint! :smile:

    Well, "rationalize" means to make rational, which this doesn't, neither in the English nor in the mathematical sense.

    It actually puts a complex number into the standard x + iy form, so I'd prefer to say "put into standard form" …

    however … now you raise the point, I see that http://hyperphysics.phy-astr.gsu.edu/hbase/cmplx2.html#c2 and others do say "rationalize" … I wonder why? :redface:
     
  8. Aug 21, 2009 #7

    Mentallic

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    But it's asking to rationalize the denominator which is achieved. The denominator becomes real, and possibly rational depending on the value of s.
     
  9. Aug 21, 2009 #8
    For ex. 1/i where i is complex number. By multiplying with i / i you get i / i2 = i / (-1), which makes the denominator real number (also rational) since I can write (-1) as (-1)/1 and the final equation would be i / (-1) / 1. Now the denominator is rational and I rationalize the equation. :smile:

    Regards.
     
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