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**1. Homework Statement**

This is a follow on question. The first few questions ask about finding the numerical answer. The question that I am confused about and cannot do seem to do properly says:

Complete the ray diagram to locate the position of the image shown on the retina when effective focal length of eye is [itex]0.020m[/itex].

**2. Homework Equations**

I was given the total power of the lens+cornea as [itex]56.0D[/itex]. I calculated the focal length by [itex]f = \frac{1}{P} = \frac{1}{56} = 0.02m[/itex] to 2dp.

**3. The Attempt at a Solution**

I attempted it and drew the focal points [itex]0.02m[/itex] from the center axis which is the lens+cornea axis. They had already provided an arrow for the Image on the retina but when I drew the diagram, it didn't meet on the grid but met outside the grid that they had provided.