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Ray Diagram

  • Thread starter Air
  • Start date
Air
202
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1. Homework Statement
This is a follow on question. The first few questions ask about finding the numerical answer. The question that I am confused about and cannot do seem to do properly says:
Complete the ray diagram to locate the position of the image shown on the retina when effective focal length of eye is [itex]0.020m[/itex].


2. Homework Equations
I was given the total power of the lens+cornea as [itex]56.0D[/itex]. I calculated the focal length by [itex]f = \frac{1}{P} = \frac{1}{56} = 0.02m[/itex] to 2dp.


3. The Attempt at a Solution
I attempted it and drew the focal points [itex]0.02m[/itex] from the center axis which is the lens+cornea axis. They had already provided an arrow for the Image on the retina but when I drew the diagram, it didn't meet on the grid but met outside the grid that they had provided.
 

Answers and Replies

70
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could you indicate roughly what is the ordering of these and their separation?
retina, lens, focal point, image, object
:smile:
 
Air
202
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Basically, the grid scale was 1 small square= 0.002m. The grid had 5x5 small boxes which made up one cm square.

There is only a grid with an axis and we have to draw all the points ourself so I thought that I would need to draw the focal point 2 cm away from the y-axis.

There isn't any detail about the separation. I assume you just have to draw it approximately, showing how a real image is formed?
 

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