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Rayleigh–Ritz method - Yukawa coulomb potential
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[QUOTE="AwesomeTrains, post: 5495995, member: 497764"] Hello everyone [h2]Homework Statement [/h2] I have been given the testfunction [itex] \phi(\alpha, r)=\sqrt{(\frac{\alpha^3}{\pi})}exp(-\alpha r) [/itex], and the potential [itex] V(r,\theta, \phi)=V(r)=-\frac{e^2}{r}exp(\frac{-r}{a}) [/itex] Given that I have to write down the hamiltonian (in spherical coordinates I assume), and I have to calculate the angular momentum operator [itex] \hat{L}^2 \phi [/itex]. (This is only a part of the whole problem. a) of a), b) and c) They should have used some other symbol for the testfunction than [itex]\phi[/itex], it's kinda confusing) [h2]Homework Equations[/h2] Angular momentum operator in spherical coordinates. [h2]The Attempt at a Solution[/h2] I guess the answer is 0, because [itex] \hat{L}^2 \phi [/itex] contains derivations of [itex]\theta, \phi[/itex] which the testfunction doesn't depend on. Is this true? [/QUOTE]
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Rayleigh–Ritz method - Yukawa coulomb potential
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