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Rayleigh–Ritz method - Yukawa coulomb potential

  1. Jun 11, 2016 #1
    Hello everyone
    1. The problem statement, all variables and given/known data
    I have been given the testfunction [itex] \phi(\alpha, r)=\sqrt{(\frac{\alpha^3}{\pi})}exp(-\alpha r) [/itex], and the potential [itex] V(r,\theta, \phi)=V(r)=-\frac{e^2}{r}exp(\frac{-r}{a}) [/itex]
    Given that I have to write down the hamiltonian (in spherical coordinates I assume), and I have to calculate the angular momentum operator [itex] \hat{L}^2 \phi [/itex]. (This is only a part of the whole problem. a) of a), b) and c) They should have used some other symbol for the testfunction than [itex]\phi[/itex], it's kinda confusing)

    2. Relevant equations
    Angular momentum operator in spherical coordinates.

    3. The attempt at a solution
    I guess the answer is 0, because [itex] \hat{L}^2 \phi [/itex] contains derivations of [itex]\theta, \phi[/itex] which the testfunction doesn't depend on. Is this true?
     
    Last edited: Jun 11, 2016
  2. jcsd
  3. Jun 14, 2016 #2

    blue_leaf77

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    Science Advisor
    Homework Helper

    Yes that's true. Another way to look at it is to realize that the test function is proportional to ##Y_0^0##.
     
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