1. The problem statement, all variables and given/known data R1 = 10 kohms R2 = 15 kohms C = 0.4F Voltage source = 20 V At first, the switch is closed for a long time so that the capacitor reach its steady-state condition. Then, the switch is opened at t=0. How much does the current flow across R_2 at t= 4ms? 2. Relevant equations I = I0 e^(-t/RC) 3. The attempt at a solution I'm a bit confused about the voltage of capacitor at t=0. Is it equal to the voltage source? Or, is it equal to the voltage at R_2 resistor since it's in parallel with it (by using the voltage divider at loop 1, we get the voltage at R_2)?