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awakeinroom8
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Homework Statement
A capacitor is placed parallel across a resistive load in a circuit. C= 0.829*10-6 F and R = 229 ohms. What fraction of the current goes through the capacitor when the frequency is 100 sec-1?
Homework Equations
I(resistor) = V/R
I(capacitor) = C * (dV/dt) = ω*C*V (?)
The Attempt at a Solution
Ic / (Ir + Ic) = [ω*C*V] / [(V/R) + (ω*C*V)] reduces to [ω*C*R] / [1 + ω*C*R]
The answer I got was 0.106569. I don't know if the work is wrong or if the format of my answer wrong, like is that the "fraction" or do I have to do something else to it? Thanks.