1. The problem statement, all variables and given/known data ok erm, i know how to get the equation V = EMF (1 - e^(-t/RC)) in a RC circuit but what if i had to take into account the internal resistance r of the voltmeter measuring the voltage across the capacitor? meaning now, the circuit contains a resistor R in series with, an internal resistance r parallel with capacitor C. so how does the equation becomes V = EMF ( r / R+r) ( 1 - e^-((R+r)t/RrC)) so by kirchoffs law, EMF = voltage across resistance R + voltage across the [parallel capacitor C and internal resistance r] EMF = RI + q/C , heres the problem, the current through the parallel component will split up into r and C. so how do i form the new equation? also will the voltage drop across the capacitor still be the same as when there is no r? so, will it still be q/C? or something else? please help thanks!