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Re:Statistics: Applications of sampling thoery

  1. Mar 21, 2004 #1

    Moved from statistics -


    I'm doing some homework over the break (!) so I don't have access to my usual lines of help. I've hit a wall:

    I don't really know how to solve a problem like this, from the replies to the previous thread I know I have no idea of the concepts being discussed here.


    I get the mean correctly, but the standard deviation does not come out correctly, it integrates to sqrt(2) / 12. Its supposed to be a normal distribution, with mean of 0 and standard deviation of 1, but damned if I know how to integrate the standard deviation correctly:

    (this is correct, the notation is standard for the TI-89)

    mu = mean = integral( w * sqrt(18) * (w-(2/3)),w,0,1 ) = 0

    var = integral(w^2 * sqrt(18) * (w-(2/3)),w,0,1) - mu^2 = sqrt(2) / 12

    (this is incorrect, the root of the answer [the standard deviation] is clearly not 1. I think I may in fact be mixing up my equations.)

  2. jcsd
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