(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Re: This Week's Finds in Mathematical Physics (Week 232)

In article <20060610152605.CF2D11310F5@mail.netspace.net.au>, Greg Egan

<gregegan@netspace.net.au> wrote:

> Ralph Hartley wrote:

[snip]

> >An *arbitrary* spacelike surface can have curvature anywhere, not just

> >at the particles.

>

> Good point! Your comment made me think of the hyperbolic plane, and the

> opportunity it gives for the sums of angles in triangles to be less than

> 2pi.

>

[snip description of a 2-particle model with spacetime foliated by

hyperboloids]

> [W]e can't

> extend things back into the indefinite past, though it might be possible

> to get around that with some further tricks.

I can't see how to extend this solution to infinite -ve time, but why not

make a virtue out of necessity and consider a family of Big Bang style

solutions which start from a singularity?

If we pick an origin in Minkowski spacetime, we can take the topological

interior of the forward light cone of the origin and declare that this

set, minus some wedges excluded along particle world lines, will be our

entire solution.

If we have a collection of world lines starting from the origin (which

itself is excluded), we then cut out wedges around them and identify the

opposite faces to give these particles various masses. If we were using

all of Minkowski spacetime for our solution, we would need to be sure

that the wedge cut out around one worldline never overlapped with that of

any other particle, but in this case instead we only have to be sure that

there's no overlap *inside the light cone*.

That allows the particle masses to be greater than they otherwise would

be, and this is what enabled the extra mass in the construction I

described in my previous post, where two particles each with deficit

angles approaching 2pi are possible.

The same construction extends naturally to a symmetrical configuration of

N particles, each of mass m. If we arrange their worldlines

symmetrically around the origin of our chosen coordinate system, the

maximum possible value of m will occur when two wedge planes associated

with two neighbouring particles meet precisely on the light cone. Take

one particle's world line to lie on the xt plane, and to be generated by

the timelike vector:

u = (1,v,0)

The two wedge planes for this world line will pass through null vectors

that are halfway to this particle's clockwise and counterclockwise

neighbours. These null vectors are:

q1 = (1, cos pi/N, sin pi/N)

q2 = (1, cos pi/N, -sin pi/N)

Normals to these planes are:

n1 = (v, 1, (v-cos(pi/N))/sin(pi/N) )

n2 = (v, 1, -(v-cos(pi/N))/sin(pi/N) )

c = n1.n2 / |n1||n2| =

(cos(pi/N)^2 - 2) v^2 + 2 cos(pi/N) v - cos(2pi/N)

--------------------------------------------------

(cos(pi/N) v - 1)^2

The deficit angle associated with each particle is then:

A = pi - arccos(c) v < cos(pi/N)

pi + arccos(c) v >= cos(pi/N)

where 0 <= arccos <= pi.

Between v=0 and v=1 (where these endpoints should be taken only as

limiting cases, not values that can actually be achieved):

v c A

---------- ------------ ------------

0 -cos(2pi/N) 2pi/N

cos(pi/N) 1 pi

1 -1 2pi

So in the high-velocity limit v->1 each particle has a deficit angle

approaching 2pi.

For 0 < v < cos(pi/N), in the many-particle limit N->infinity we have a

(maximum) total deficit angle of:

N A -> 2pi sqrt((1+v)/(1-v))

This means that if we want a system with a scalar sum of rest mass equal

to M (which, with a certain choice of units, means a total deficit angle

of 2M), there will be a minimum velocity required in these models of:

v_min = (M^2 - pi^2) / (M^2 + pi^2)

For, say, M=4.5pi, v_min = 0.905. Interestingly, this comes at a point

where the total holonomy has ceased to be cyclic in v; see the plots at

the end of:

http://gregegan.customer.netspace.net.au/GR2plus1/GR2plus1.htm [Broken]

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# Re: This Week's Finds in Mathematical Physics (Week 232)

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