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An L-shaped bar is constrained by a fixed support at A while the other extreme C is free. Determine the reaction at the point A when the bar is loaded by the depicted forces.

Data:

[tex]AB=3m, BC=2m, CD=1m[/tex]

[tex]R_B=3N[/tex]

[tex]R_{Cx}=6N, R_{Cy}=2N, R_{Cz}=3N[/tex]

Either I'm doing something wrong or there's more than enough data in the problem. I assume we just have to write the three equations of equilibrium:

[tex]\sum{R_{ix}}=R_{Ax}-R_B-R_{Cx}=0[/tex]

[tex]\sum{R_{iy}}=R_{Ay}-R_{Cy}=0[/tex]

[tex]\sum{R_{iz}}=R_{Az}-R_{Cz}=0[/tex]

Then we just calculate their resultant in order to find [tex]R_B[/tex]. If so, then why would we need all those distances?

Maybe my assumptions are plain wrong, I'm really confused... Help appreciated. Thanks.

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# Homework Help: Reaction at a fixed support

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