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I have this reaction formula

[itex]

CH_{4} + 2O_{2} \rightarrow 2H_{2} O + CO_{2}

[/itex]

CH4 and O2 are contained in a canister which has a volume V = 500 Liters.

The mass of CH4 is 100 grams and O2 has a mass of 100 grams.

I have two questions:

First if I want to calculate the mass of the generated [itex]CO_2[/itex].

Can't this be done by the following calculation

[itex]

n(CH_4) = n(CO_2) \ \rightarrow \ n(CO_2) = \frac{m(CH_4)}{M(CH_4)} = ??

[/itex]

And then multiply it with [itex]M(CO_2)[/itex] ??

Second: if the temperature in the canister is messured to be 105 degrees celcius at the end of the above reaction. How do I calculate the partial pressure of [itex]CH_{4}[/itex] at this temperature ??

Many Thanks in advance :)

Sincerely Fred

Denmark

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# Reaction Formula

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