- #1

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## Homework Statement

##_{1}^{2}\textrm{D}+_{1}^{3}\textrm{T}\rightarrow _{4}^{2}\textrm{He}+n##

How much energy releases?

## Homework Equations

Semi empirical mass formula that we use:

##W=-w_0A+w_1A^{2/3}+w_2\frac{Z(Z-1)}{A^{1/3}}+w_3\frac{(a-2Z)^2}{A}+w_4\frac{\delta _{ZN}}{A^{3/4}}##

for

##w_0=15.6MeV##, ##w_1=17.3MeV##, ##w_2=0.07MeV##, ##w_3=23.3MeV## and ##w_4=33.5MeV##.

## The Attempt at a Solution

Now we did plenty of examples yet elements usually had much more neutrons than this reaction, meaning we could simply forget if there were any additional neutrons on the RHS of the reaction.

This is obviously not the case and I have no idea what to do with that extra neutron.

For everything else:

##W=W(He)+W(n)-W(D)-W(T)##

##W=-29.768MeV+W(n)-16.18MeV+3.047MeV##

I hope all the numbers are ok. The result should be 17.6 Mev.