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## Homework Statement

N2O4 --------------> NO2 N2O4 for k = 0.050 s-1

The process starts from 0.20 mole of N2O4 in a container of 4.0L. Calculate v for N2O4.

if 3/4 of the N2O4 is converted

## Homework Equations

To calculate concentration

c= mole/L

## The Attempt at a Solution

0.20 mole /4.0 L =0.05 M

(3/4)x0.05 =0.0375 M

V(reaction rate) = k .0.0375M

v= 0.050 s-1 x 0.0375 M

v=0.001875

But the answer should be 6.3x10^-4 [/B]