1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Reaction rate

  1. Jan 21, 2016 #1
    1. The problem statement, all variables and given/known data
    N2O4 --------------> NO2 N2O4 for k = 0.050 s-1
    The process starts from 0.20 mole of N2O4 in a container of 4.0L. Calculate v for N2O4.
    if 3/4 of the N2O4 is converted

    2. Relevant equations
    To calculate concentration
    c= mole/L

    3. The attempt at a solution
    0.20 mole /4.0 L =0.05 M
    (3/4)x0.05 =0.0375 M
    V(reaction rate) = k .0.0375M
    v= 0.050 s-1 x 0.0375 M
    v=0.001875
    But the answer should be 6.3x10^-4
     
  2. jcsd
  3. Jan 21, 2016 #2

    Borek

    User Avatar

    Staff: Mentor

    How much is left

    ?
     
  4. Jan 21, 2016 #3

    Suraj M

    User Avatar
    Gold Member

    How did you arrive at this?
     
  5. Jan 22, 2016 #4

    Borek

    User Avatar

    Staff: Mentor

    That's a given.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Reaction rate
  1. Rate of reaction (Replies: 2)

  2. Rate of Reaction (Replies: 2)

  3. Rate of Reaction? (Replies: 5)

  4. Reaction rates (Replies: 1)

  5. Rate of Reaction (Replies: 17)

Loading...