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Reaction rate

  1. Jan 21, 2016 #1
    1. The problem statement, all variables and given/known data
    N2O4 --------------> NO2 N2O4 for k = 0.050 s-1
    The process starts from 0.20 mole of N2O4 in a container of 4.0L. Calculate v for N2O4.
    if 3/4 of the N2O4 is converted

    2. Relevant equations
    To calculate concentration
    c= mole/L

    3. The attempt at a solution
    0.20 mole /4.0 L =0.05 M
    (3/4)x0.05 =0.0375 M
    V(reaction rate) = k .0.0375M
    v= 0.050 s-1 x 0.0375 M
    But the answer should be 6.3x10^-4
  2. jcsd
  3. Jan 21, 2016 #2


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    Staff: Mentor

    How much is left

  4. Jan 21, 2016 #3

    Suraj M

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    Gold Member

    How did you arrive at this?
  5. Jan 22, 2016 #4


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    Staff: Mentor

    That's a given.
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