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  • Thread starter Nanu Nana
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  • #1
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Homework Statement


N2O4 --------------> NO2 N2O4 for k = 0.050 s-1
The process starts from 0.20 mole of N2O4 in a container of 4.0L. Calculate v for N2O4.
if 3/4 of the N2O4 is converted

Homework Equations


To calculate concentration
c= mole/L

The Attempt at a Solution


0.20 mole /4.0 L =0.05 M
(3/4)x0.05 =0.0375 M
V(reaction rate) = k .0.0375M
v= 0.050 s-1 x 0.0375 M
v=0.001875
But the answer should be 6.3x10^-4 [/B]
 

Answers and Replies

  • #2
Borek
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  • #3
Suraj M
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if 3/4 of the N2O4 is converted

How did you arrive at this?
 
  • #4
Borek
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