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Reaction Rates Explanation?

  1. Oct 7, 2009 #1
    Experiments show that the following redox reaction is second-order overall:

    NO2(g) + CO(g) --> NO(g) + CO2(g)

    In the reaction, the initial [NO2] is twice the initial [CO]. What is the ratio of the initial rate to the rate at 50% completion?

    In the solution they say: [NO2]i = 2[CO]i

    and then at 50% completion they say: [CO] = 1/2[CO]i and [NO2] = 0.75[NO2]i

    where they getting the 1/2 and 0.75 from?
  2. jcsd
  3. Oct 8, 2009 #2


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    Staff: Mentor


  4. Oct 8, 2009 #3
    how? can you show the math behind it?

    I dont see how they can get .75 if its at 50% completion. Wouldnt that mean NO2 is at 1.5 and CO is at 1? But they cant be since NO2 is twice the initial CO
  5. Oct 8, 2009 #4


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    Staff: Mentor

    They react 1:1, if half of the CO reacted, how much NO2 was left?

    Edit: note, that 1.5/2=0.75...

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