Assume a single-phase AC voltage applied to a series circuit with a certain impedance. Because of the real and imaginary part of the impedance, we get both real and reactive power. Now, if we were to connect a capacitor in parallel with the circuit, and if this capacitor supplies a certain amount of vars, what happens to the total reactive power of the circuit? My intuition tells me that:(adsbygoogle = window.adsbygoogle || []).push({});

P(total) is unchanged because the capacitor is purely reactive.

Q(total) = Q(source_before) = Q(source) + Q(cap)

So basically by adding that capacitor, you're reducing the the reactive power supplied by the voltage source, and thus increasing the power factor. Am I right?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Reactive Power Question

**Physics Forums | Science Articles, Homework Help, Discussion**