1. The problem statement, all variables and given/known data The circuit in the attached figure (excuse the terrible drawing, I suck at using the paint feature) all meters are idealized and the batteries have no appreciable internal resistance a) Find the reading of the voltmeter with the switch S open b) With the switch closed, find the reading of the voltmeter and the ammeter. Which way does the current flow through the switch? 2. Relevant equations V = I/R (ohm's law) [tex]\Sigma[/tex]I = 0 (junction law) [tex]\Sigma[/tex]V = 0 (loop law) 3. The attempt at a solution To find the reading of the voltmeter I attempted to find the currents going through the 2 emf's and then using the junction rule to find current at point a (the top) and then using ohm's law with that current and the 75 ohm resistor to find the reading of the voltmeter, with the switch open I treated that segment as if the switch line wasn't there, here's what I got for loop 1 (with the 25V emf) 25V-I1(100 ohms) = 0 25V = I1(100ohms), I1 = .25A for loop 2 (with the 15V emf) 15V-I2(75 ohms) = 0 15V = I2(75 ohms), I2 = .20A junction rule .25A-.20A-I = 0, I = .05A ohm's law for voltmeter I = V/R, V = IR -> V = (.05A)(75ohms) = 3.75V I'm not sure if I did the question correctly, if any one can check it for me I would appreciate it, thank you.