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Real Analysis proof (simple)

  1. Mar 27, 2008 #1
    1. The problem statement, all variables and given/known data
    Using a delta epsilon method prove:
    [tex]\mathop {\lim }\limits_{x \to 1 } x^3+2x^2-3x+4= 4[/tex]

    3. The attempt at a solution
    I got so far as breaking the equation into

    [tex]=|x||x+3||x-1|[/tex] now how do I bound it? Also, even more basic question, once I found the bound how do I put the whole thing together as a proof? I do not want you to prove this one, but please, if you can provide a link to a similar problem for me to see how it flows from idea, to figuring out the bounding, to the scratch work of figuring out epsilon, to the actual proof write up. Like the whole flow of things.

    I am very familiar with "standard" proofs, but very much lost on the real analysis ones... We have a very bad book with no examples but mainly some ideas, definitions and a ton of homework.

    Thank you in advance
  2. jcsd
  3. Mar 27, 2008 #2
    well you need to show that

    [tex]\forall\epsilon>0,\exists\delta(\epsilon)>0, \ \ such \ \ \ that \ \ \ whenever \ \ \ \\ \ \

    0<|x-1|<\delta => |x^{3}+2x^2-3x+4-4|<\epsilon ????[/tex]

    Now from here we go:


    lets see, since x-->1 , it is safe to assume that

    [tex]0<x<2=>|x|<2[/tex] also [tex]0<x<2/+3 => 3<x+3<5=>|x+3|<5[/tex]
  4. Mar 28, 2008 #3


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    In order to be completely "safe" one should say something like [tex]\delta[/itex]= minimum of [itex]\left{\frac{\epsilon}{10}, 1\right}[/tex].
  5. Mar 28, 2008 #4

    Yes, i forgot to add that!!
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