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Real and complex roots

  1. Nov 2, 2006 #1
    of the equation
    z= exp(-z)

    could someone possibly point me in the right direction to start this problem?
    this area of math is still new to me so please go easy
    thanks
     
  2. jcsd
  3. Nov 2, 2006 #2

    berkeman

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    I moved this thread to the homework section. gmans, what do you mean by the equation that you have written? What is "exp" representing?
     
  4. Nov 2, 2006 #3

    arildno

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    Probably, he means:
    [tex]z=e^{-z}[/tex]
     
  5. Nov 2, 2006 #4

    quasar987

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    That's a fun problem. I say start by defining z=a+ib where a and b are real numbers and also note z=|z|exp(i[itex]\Phi[/itex]) the polar form of z, so that you're looking for the solutions to

    [tex]|z|e^{i\Phi}=e^{-a-ib}[/tex]

    And use the fact that two complex numbers are equal iff their modulus are the same and their polar angle are the same up to a difference of [itex]2n\pi[/itex], [itex]n\in\mathbb{Z}[/itex].
     
    Last edited: Nov 2, 2006
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