Real and complex roots

  • Thread starter gmans
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  • #1
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of the equation
z= exp(-z)

could someone possibly point me in the right direction to start this problem?
this area of math is still new to me so please go easy
thanks
 

Answers and Replies

  • #2
berkeman
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I moved this thread to the homework section. gmans, what do you mean by the equation that you have written? What is "exp" representing?
 
  • #3
arildno
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Probably, he means:
[tex]z=e^{-z}[/tex]
 
  • #4
quasar987
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That's a fun problem. I say start by defining z=a+ib where a and b are real numbers and also note z=|z|exp(i[itex]\Phi[/itex]) the polar form of z, so that you're looking for the solutions to

[tex]|z|e^{i\Phi}=e^{-a-ib}[/tex]

And use the fact that two complex numbers are equal iff their modulus are the same and their polar angle are the same up to a difference of [itex]2n\pi[/itex], [itex]n\in\mathbb{Z}[/itex].
 
Last edited:

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