hello all(adsbygoogle = window.adsbygoogle || []).push({});

just studying to that crazy electrical engineering 2 exam coming up friday

encountered something weird about power dissipation.

Given is an AC circuit, source of 10V f=100Hz Z=20 Ohm

Matched to give maximum power is the load impedance which will be 20 Ohm as well.

now my problem:

I have assumed to calculate the current (10V/40 Ohm = 0.25A) and then easily apply I^2*V which gave 1.25W now, in the answer sheet is given solution just half of it : 625mW

now ... why did they divide it by two? how should I know when to do that ? is that a different method I should apply for DC / AC circuits ? does it make any difference that it is calledimpedanceand notressistance

Thank you all for you time people

Greets, Amit.

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# Real Power in AC circuit:cry:

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