The ∂B(0,1) in R is the set {-1,1} so(adsbygoogle = window.adsbygoogle || []).push({});

∫f over ∂B(0,1) in R = f(1) - f(-1) ?

Or would it be interpreted differently? This is a really basic question that for some reason I can't answer confidently for myself. I'm mainly dealing with averages and I'm trying to figure out what that would look like over the boundary of the ball in R^{1}. Then, would the volume of that set just be 2?

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# Really easy question about boundaries.

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