- #1
UrbanXrisis
- 1,196
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I need to calculate thr force required to pull a copper ball of radius 2cm upwards through a fluid at the costant speed of 9 cm/s. The drag force is porportional to the speed with porportionality constant 0.950 kg/s. Ignoring the buoyant force, I need to caluate the force.
I fould out the mass=2 .67E-4 kg, after finding copper's density then m=d/v
I think in the end, I will go back to the equation F=ma. So, I need to find acceleration:
a=g-bv/m
b=porportionality constant 0.950 kg/s
v=costant speed of 9 cm/s
m=2 .67E-4 kg
what in the world would g equal? Any help is appreciated
I fould out the mass=2 .67E-4 kg, after finding copper's density then m=d/v
I think in the end, I will go back to the equation F=ma. So, I need to find acceleration:
a=g-bv/m
b=porportionality constant 0.950 kg/s
v=costant speed of 9 cm/s
m=2 .67E-4 kg
what in the world would g equal? Any help is appreciated