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Really need help in finding the acceleration for "built" boxes.
Small block 1 with mass m = 2.56 kg sits on top of large block 2 of mass M = 7.7 kg, and the pair sit on a frictionless, horizontal table. Between the blocks: the coefficient of kinetic friction is μk = 0.146, and the coefficient of static friction is μs = 0.203.
Now, suppose the force applied to block 1 has magnitude F = 22.6 N, which is greater than 6.79 N. Find the magnitude of the acceleration of each block.
→ magnitude of the acceleration of block 1 (top block)
→ magnitude of the acceleration of block 2 (bottom block)
→F = ma.
→ΣF_up = ΣF_down
→ΣF_left = ΣF_right
→Newtons' Laws of Motion
Drew the FBD [free body diagram] (see attachment) and can't seem find the way to approach the problem.
Homework Statement
Small block 1 with mass m = 2.56 kg sits on top of large block 2 of mass M = 7.7 kg, and the pair sit on a frictionless, horizontal table. Between the blocks: the coefficient of kinetic friction is μk = 0.146, and the coefficient of static friction is μs = 0.203.
Now, suppose the force applied to block 1 has magnitude F = 22.6 N, which is greater than 6.79 N. Find the magnitude of the acceleration of each block.
→ magnitude of the acceleration of block 1 (top block)
→ magnitude of the acceleration of block 2 (bottom block)
Homework Equations
→F = ma.
→ΣF_up = ΣF_down
→ΣF_left = ΣF_right
→Newtons' Laws of Motion
The Attempt at a Solution
Drew the FBD [free body diagram] (see attachment) and can't seem find the way to approach the problem.
Homework Statement
Homework Equations
The Attempt at a Solution
Attachments

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