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Really quick easy question

  1. Mar 15, 2005 #1
    Ok sorry for this..small, stupid obvious question...but here it is..

    i need to solve for k in:

    e^10k = .75

    So do i just take the natural log of both sides...and then the 10k should come down and i can just solve for k from that, right?
  2. jcsd
  3. Mar 15, 2005 #2

    Unfortunately this board won't let me make a four letter reply, so I have to add this pointless line :)
  4. Mar 15, 2005 #3
    ok great..thanks a lot..
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