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: really quick simplifying radical question

  1. Jun 12, 2005 #1
    hey, just a really quick question, any help wud be great,

    is it possible to simplify this radical further?

    p = sqrt root (6/70q^2)

    thx in advance for help.
     
  2. jcsd
  3. Jun 12, 2005 #2

    OlderDan

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    Certainly. The ratio of two even numbers can always be simplified. Any time you have the square root of a square, you can simplify, though you do need to be careful. If q is any real number, then when you take the square root you cannot simply write q in the simplified expression, you need to write the absolute value of q. In most problems of this sort, variables are treated as postive quantities, but you need to check the context of the problem.
     
  4. Jun 12, 2005 #3
    the question stated q is greater than 0, therefore q is pos. but how would u simplify this since q does not have a number value?
     
  5. Jun 12, 2005 #4

    OlderDan

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    If it were a number like 5, what would say about sqr root (5^2)? Change 5 to any other number, including fractions like 1/5. What must be true in general?

    And remember that sqr root (a*b) = (sqr root(a))*(sqr root (b))
     
  6. Jun 12, 2005 #5

    DDS

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    p=sqrt 3/35q^2
     
  7. Jun 12, 2005 #6

    OlderDan

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    p=sqrt (3/35q^2). Keep going
     
  8. Jun 12, 2005 #7

    DDS

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    older dan do u mind checking your private messages and reisitng some of my work on my posts as well..

    please and thank u
     
  9. Jun 12, 2005 #8
    i got it

    its sqrt105 /35q
     
  10. Jun 12, 2005 #9

    OlderDan

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    I don't think so. Where does 105 come from? You need to use parantheses to show what is in the square root and what is not.
     
  11. Jun 12, 2005 #10
    ok maybe u guys got orginial Question wrong.

    it's actually p = sqrt root (6 / 70q^2)

    so becomes sqrt 6 / sqrt 70 sqrt q^2

    so becomes sqrt 6 / sqr 70 q

    sqrt 6 * sqrt 70 / 70q

    sqrt 420 / 70q

    sqrt 105 / 35 q
     
  12. Jun 12, 2005 #11
    Theres alot of algebra going wrong there.

    [tex] \sqrt{\frac{6}{70q^2}} [/tex]

    [tex] \frac{\sqrt{6}}{\sqrt{70q^2}} [/tex]

    [tex] \frac{\sqrt{2}\sqrt{3}}{\sqrt{2}\sqrt{35}\sqrt{q^2}} [/tex]

    Do you follow that? That's one way to do it. Complete the process.
     
  13. Jun 12, 2005 #12
    yeah dude, .... ok so u get

    sqrt 3 / sqrt 35 q

    now u multiply by sqrt 35 / sqrt 35

    and u get sqrt 105 / 35 q

    ..................... lol....
     
  14. Jun 12, 2005 #13
    You really should use parentheses.
     
  15. Jun 12, 2005 #14
    lol yeah i gotta learn the things u guys use to write symbols out.
     
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