I just got my calculus midterm back, and I lost one mark on an area problem. I did the problem properly, but I may have made a mistake at the end. I end up with arctan1-1/2ln3-1/2ln1 (this step did not have an "x") I simplified this to pi/4-1/2ln3 (here, the grader put a 2 over my 3 in ln3) then I made it pi/4-ln(3^1/2) (there was a question mark around this) so my quick questions are: why was there are 2 over my three? (I thought 1/2ln1 was equal to zero.) why was there a question mark around the last part (I thought alnx was equal to ln(x^a) Hopefully this makes sense, post and I can clarify thanks SO much in advance if you helped!