Suppose a 50kg block slides along a horizontal surface where the coefficient of kinetic friction between the block and the surface is uk = 0.60. A force F = 400 N is now applied, where the angle of the force above horizontal is 20°. What is the magnitude of the acceleration of the block? 0.54 m/s2 2.31 m/s2 3.27 m/s2 6.78 m/s2 8.11 m/s2 Here's what i did: F(x-net) = F(applied) - F(friction) = ma a = F(applied) - F(friction) / m = (400)(cos 20) - (50 * 9.8 * 0.6) / 50 = 375 N - 294 N / 50 kg = 1.67 m/s2 I checked my numbers quite a few times and keep getting 1.67, which is not one of the answer choices. The only thing I saw was that 3.72 m/s2 is exactly double what I got, but I can't find an explanation for that. Thanks!