Assuming idealized springs under Hooke's Law: A spring 1m in length, mounted on the ground, compresses 10cm under its own weight. Next to it is a spring identical in material, construction, etc., but 2m long with twice the mass. If I understand correctly, doubled weight alone would suggest compression of 20cm. BUT, at twice the length, the spring constant (k) is halved. Thus, the expected compression is actually 40cm. Is this correct?