Rearrange the Projectile Motion equation

  • Thread starter mlbmaniaco
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  • #1
mlbmaniaco
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I have a real big problem. My physics teacher has given an extra-credit assignment to my class to figure out. He said we can use whatever we want to figure it out. The problem was to rearrange the Projectile Motion equation (d = Vit + 1/2at2) to solve for t.

So I started out by asking my Math B2 teacher if she knew how to figure it out. After 15 minutes of work she got t = (d/t -vi) 2/a. But she didn't know how to get the second t out of the equation. We both ended up going over to the other math teacher. He got the same thing. Now the three of us are determined to figure out this answer. Can any physics wizard out there help us? All I want to know is how to rearrange the Projectile Motion equation (d = Vit + 1/2at2) to solve for t. For. Example F=ma, to rearrange the equation to sovle for m, it would be m=f/a. So I Want t= ? So can anyone help?
-Puzzled Student
 

Answers and Replies

  • #2
Poncho
29
0
This equation is of the form

[tex]
ax^2+bx +c = 0
[/tex]

Use the quadratic formula to solve

[tex]
x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}
[/tex]
 
  • #3
BobG
Science Advisor
Homework Helper
330
85
They'll probably kick themselves (this sounds like the classic case of getting your eyes so close to the problem they can't see it). Surely, both of them have heard of the quadratic formula.

[tex]d=vt + \frac{1}{2} at^2[/tex]
[tex]\frac{1}{2} at^2+vt - d = 0 [/tex]
[tex]t = \frac{-v \pm \sqrt{v^2+4 \left( \frac{1}{2} a\right)d}}{2 \left( \frac{1}{2} a \right)}[/tex]
 
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