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Rearranging Equation

  1. Jun 3, 2009 #1
    1. The problem statement, all variables and given/known data

    3x[tex]^{2}[/tex] + 2y[tex]^{2}[/tex] = 35

    2. Relevant equations



    3. The attempt at a solution
    I rearrangged it for x[tex]^{2}[/tex] and got [tex] -\frac{2}{3}y+11\frac{2}{3}=x^{2}[/tex]
    Is this right?
     
  2. jcsd
  3. Jun 3, 2009 #2

    rock.freak667

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    It looks correct to me
     
  4. Jun 3, 2009 #3
    I don't think it is 11(2/3)

    [itex]3x^2 + 2y^2=35[/itex]
    [itex]3x^2 = 35 - 2y^2[/itex]
    [itex]x^2 = 35/3 - (2/3)y^2[/itex]

    but [itex]35/3 = 11(2/3)[/itex]?
    [itex]11.66.. \neq 7.33..[/itex]
     
  5. Jun 3, 2009 #4

    rock.freak667

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    I believe [itex]11\frac{2}{3}[/itex] meant 11 and 2/3 not 11 multiplied by 2/3
     
  6. Jun 3, 2009 #5

    HallsofIvy

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    But it should be
    [tex]x^2= -\frac{2}{3}y^2- 11\frac{2}{3}[/tex]
    Not
    [tex]x^2= -\frac{2}{3}y- 11 \frac{2}{3}[/tex]

    I presume the missing exponent on y was a typo.
     
  7. Jun 3, 2009 #6
    lol. Mixed numbers. It has been so long since i last used them and it should be best to be avoided.
     
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