- #1

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P{X(n)=m}=SUM(from 1, to n-1)(p(n,k)*P{X(k)=m-1}

P{X(0}=0}=1 P{X(1)=0}=1

p(n,k)-some const witch depends on n and k.

I need full solvation of this problem.

Thanks for help.

- Thread starter vtakhist
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- #1

- 11

- 0

P{X(n)=m}=SUM(from 1, to n-1)(p(n,k)*P{X(k)=m-1}

P{X(0}=0}=1 P{X(1)=0}=1

p(n,k)-some const witch depends on n and k.

I need full solvation of this problem.

Thanks for help.

- #2

- 102

- 1

WHAT is p{X(n)=m} ???? apart from other things

- #3

- 11

- 0

Probability, that random variable X(n) will take a value m.

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