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Reconnection of capacitors

  1. Oct 24, 2015 #1
    In an example from my textbook, two capacitors are fully charged and then disconnected from the battery. (The full text is on the bottom of the thread).
    Screenshot (71).png
    Initially, the positive charge is on top, negative on the bottom.
    Screenshot (72).png
    How did this occur? This is the part that I don't understand. Originally the top had two positive charges and now it has both positive and negative. Is this natural, or was something done during the re-connection?
    Screenshot (70).png
    So the charges move back to the same configuration as in (A) - positive on top, negative on the bottom. This makes sense. Once again, I don't understand part B, because part B doesn't seem to fit the sequence. A can go to C, but B doesn't fit.

    Below is the full example, if it helps
    Screenshot (73).png
    Thank you.
     
  2. jcsd
  3. Oct 24, 2015 #2

    Filip Larsen

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    Gold Member

    Looks like C2 is simply "turned around" between the two first diagrams, i.e. the connectors between C1 and C2 are swapped in the second diagram compared to the first.
     
  4. Oct 24, 2015 #3

    Dale

    Staff: Mentor

    Read the second sentence of the first paragraph of the question. Carefully.
     
  5. Oct 24, 2015 #4

    davenn

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    Science Advisor
    Gold Member

    Yes

    and yes :smile:
     
  6. Oct 25, 2015 #5

    jbriggs444

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    Science Advisor

    You may want to re-think that. The removal of the battery leaves the system in the state shown at (a). It is already in equilibrium and no charge will flow.
     
  7. Oct 25, 2015 #6
    Yeah it is. Sorry for that. I'll jus delete the previous post. Thanks!
     
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