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Rectangular Potential Barrier

  1. Apr 6, 2010 #1
    Barrier potential, E> V0

    V(X) = 0 ( x < 0 )
    = V0 ( 0 < x < a )
    = 0 ( x> a )

    Psi(x)1 = Aexp[ik1x] + B exp[-ik1x]
    Psi(x)2 = Cexp[ik2x] + D exp[-ik2x]
    Psi(x)3 = Fexp[ik1x] + G exp[-ik1x] ( K3= K1 so I put k1 )

    and G = 0 because there is no reflection,

    I used B.C so I get 4 functions
    and I calculated and I found what is A/F .
    but there is problem
    exp[ik2a] and exp[-ik2a], I changed into sine and cosine
    but there is remaind exp[ik1a]

    I have to derive T(transmission) but there is no K1
    how do I eliminate that?

    this problem is from Introductory Nuclear Physics chap.2 - 1
    please help me :(
     
  2. jcsd
  3. Apr 6, 2010 #2
  4. Apr 8, 2010 #3
    my Q was how I change t to T in wikipedia where you link.
    why there is sine fomula?

    but, finally I've done :)
    thank you
     
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